| ▲ | DrBazza 3 hours ago | ||||||||||||||||
If I add water to a glass of whiskey and dilute it, why don't I get twice as drunk? | |||||||||||||||||
| ▲ | qsera 3 hours ago | parent | next [-] | ||||||||||||||||
But you can drink a lot more that way and get way more drunk! | |||||||||||||||||
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| ▲ | OutOfHere an hour ago | parent | prev [-] | ||||||||||||||||
Because the amount of total intoxicant is the same. Let: A = amount of ethanol V = initial whiskey volume W = added water Initial concentration: c₁ = A / V After dilution: c₂ = A / (V + W) If you drink the entire diluted glass: ethanol consumed = c₂(V + W) = A Intoxication ∝ ethanol consumed Therefore: drunkenness ∝ A not ∝ (V + W) Adding water changes concentration, not the total ethanol: A = constant ⇒ drunkenness = constant (ignoring effects of drinking rate). | |||||||||||||||||