| ▲ | OutOfHere 2 hours ago | |
Because the amount of total intoxicant is the same. Let: A = amount of ethanol V = initial whiskey volume W = added water Initial concentration: c₁ = A / V After dilution: c₂ = A / (V + W) If you drink the entire diluted glass: ethanol consumed = c₂(V + W) = A Intoxication ∝ ethanol consumed Therefore: drunkenness ∝ A not ∝ (V + W) Adding water changes concentration, not the total ethanol: A = constant ⇒ drunkenness = constant (ignoring effects of drinking rate). | ||