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hyperhello 6 hours ago

eml(1,eml(x,1)) = eml(eml(1,x),1) = exp(ln(x)) = ln(exp(x)) = x

thaumasiotes 4 hours ago | parent | next [-]

But f(x) = eml(1, x) and g(x) = eml(x, 1) are different operations. What operation are you saying is supposed to be its own inverse?

freehorse 2 hours ago | parent | prev [-]

eml(1,eml(x,1)) = e + x

and

eml(eml(1,x),1) = e^e * x

hyperhello 6 minutes ago | parent [-]

Okay, I’m tired. Not quite inverse but per the title , must be a way.