eml(1,eml(x,1)) = e + x

and

eml(eml(1,x),1) = e^e * x

Okay, I’m tired. Not quite inverse but per the title , must be a way.

	▲	freehorse 32 minutes ago \| parent [-]
		I was mistaken above in the first identity, it is eml(1,eml(x,1)) = e - x Which then if you iterate gives x (ie is inverse of itself). eml(1,eml(eml(1,eml(x,1)),1)) = x