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| ▲ | alacritas0 4 hours ago | parent | next [-] |
| If you add 5.1kΩ pulldown resistors on the CC lines for USB-C, you can get the standard 5V without a handshake although current may be limited by some chargers without negotiation. |
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| ▲ | amstan an hour ago | parent | prev | next [-] |
| I think you're overstating this. The "handshake" is purely 2 simple resistors correctly installed. The problem is a lot of folks do it wrong for various reasons, most likely never testing with anything more than type a to type c cables. https://people.kernel.org/bleung/how-to-design-a-proper-usb-... |
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| ▲ | hdgvhicv 2 hours ago | parent | prev | next [-] |
| One of the many deficiencies of usb-c (who knows what power your cable supports, charger supports, if you accessory will charge, of it will connect at all) |
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| ▲ | vscode-rest 5 hours ago | parent | prev [-] |
| Interesting. Does UsBC spec/licensing require any sort of notation for products that don’t implement handshake? |
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