> Rust isn't special in this regard, it has the same issues.

This is both fundamentally true and misleading. Rust has to solve the same issues but isn't obliged to make all the same bad choices to do that and so the results are much better.

For example C++ dare not perform compile time transmutations so, it just forbids them and a whole bunch of extra stuff landed to work around that, but in Rust they're actually fine and so you can just:

    const FOO: bool = unsafe { core::mem::transmute::<i8, bool>(2) };

That blows up at compile time because we claimed the bit pattern for the integer 2 is a valid boolean and it isn't. If we choose instead 0 (or 1) this works and we get the expected false (or true) boolean instead of a compiler diagnostic.

C++ could allow this but it doesn't, rather than figure out all the tricky edge cases they just said no, use this other new thing we made.

▲ jandrewrogers 6 hours ago | parent | next [-]

> For example C++ dare not perform compile time transmutations

I am confused by this assertion. You can abuse the hell out of transformations in a constexpr context. The gap between what is possible at compile-time and run-time became vanishingly small a while ago.

I think your example is not illustrative in any case. Many C++ code bases work exactly like your example, enforced at compile-time. That this can be an issue is a hangover from retaining compatibility with C-style code which conflates comparison operators and cast operators. It is a choice.

C++ can enforce many type constraints beyond this at compile-time that Rust cannot, with zero effort or explicit type creation. No one should be passing ints around.

▲ germandiago 2 hours ago | parent | prev | next [-]

In my experience conversions is one of the things that maximum warning levels do excellent static analysis for nowadays. In the last 15 years I hardly had a couole problems (init vs paren initialization). All narrowing etc. is caught out of the box with warnings.

▲ poppadom1982 3 hours ago | parent | prev [-]

I'm not sure what you're getting at but

const bool z = (const bool)((int8_t)2);

Is perfectly valid C++.

▲ debugnik 3 hours ago | parent [-]

That's a conversion, not the same. The naive equivalent to transmute would be

    int8_t x = 2;
    bool y = *reinterpret_cast<bool *>(&x);

But reinterpret_cast isn't valid in a constexpr scope.

▲

poppadom1982 2 hours ago | parent | next [-]

My point is, in your exact example both reinterpret_cast and C-style casts have the exact same behavior, making the example bad. If you want to showcase a deficiency of C++, it would make sense to pick something where the difference between cast types actually matters.

▲

TuxSH an hour ago | parent | prev [-]

> But reinterpret_cast isn't valid in a constexpr scope.

std::bit_cast is

	▲	debugnik an hour ago \| parent [-]
		Oh cool, and it behaves like memcpy, not like pointer aliasing! I'm stuck with C++14 at work so I missed that one.