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lioeters 4 hours ago

> C=A^B is also pure noise

Is C really "pure noise" if you can get A back out of it?

It's like an encoding format or primitive encryption, where A is merely transformed into unrecognizable data, meaningful noise, which still retains the entirety of the information.

LegionMammal978 4 hours ago | parent | next [-]

> Is C really "pure noise" if you can get A back out of it?

If you throw out B, then there's no possible way to get A out of C (short of blindly guessing what A is): that's one of the properties of a one-time pad.

But distributing both B and C is no different than distributing A in two parts, and I'd have a hard time imagining it would be treated any differently on a legal level.

amelius 4 hours ago | parent | prev [-]

No, C is really noise, fundamentally.

Imagine another copyrighted work D.

E=C^D, therefore C=D^E

As you see, the same noise can be used to recover a completely different work.

Since you can do this with any D, C is really noise and not related to any D or A.

lioeters 3 hours ago | parent [-]

I'm not sure I agree. In the case of new source D, C is being used as the key, not the encoded data.

> B^C gives you back A

If both B and C are pure noise, where did the information for A come from?