No, C is really noise, fundamentally.

Imagine another copyrighted work D.

E=C^D, therefore C=D^E

As you see, the same noise can be used to recover a completely different work.

Since you can do this with any D, C is really noise and not related to any D or A.

I'm not sure I agree. In the case of new source D, C is being used as the key, not the encoded data.

> B^C gives you back A

If both B and C are pure noise, where did the information for A come from?