A black hole.

A black hole is no more a perfect sphere than a sun is. Would gravity from the nearest other black hole not have a deforming effect of at least 2^-64 ?

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andrewla 7 days ago | parent | prev | next [-]

A non-rotating black hole. Or a rotating black hole with zero charge. Or a rotating black hole with non-zero charge no external magnetic fields. Or a rotating black hole with non-zero charge with non-time-varying external magnetic fields. Or a wart on a frog on a bump on the log on a hole on the bottom of the sea.

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Kranar 7 days ago | parent | prev [-]

There is no black hole that is a perfect sphere. That would, at a minimum, require a body with absolutely no angular momentum which isn't in anyway feasible.

Any rotating/spinning black hole will no longer be a perfect sphere.

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gpm 7 days ago | parent [-]

Yeah but if you look down the axis of rotation you will have a perfect (to many decimal places anyways) circle... which was the demand.

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Dylan16807 7 days ago | parent | next [-]

That might be right.

But even then, the biggest black hole we think is possible measured down to the planck length gives you a number with 50 digits. And the entire observable universe measured in planck lengths is about 60 digits.

So how are you going to get a physical pi of even a hundred digits on the path toward arbitrary precision?

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andrewla 3 days ago | parent | prev [-]

> to many decimal places anyway

> > The idea of arbitrary precision is intrinsically broken in physical reality.

There is no contradiction here.

	▲	gpm 3 days ago \| parent [-]
		Yeah I was just responding to the 64bit float thing, people overestimate floats.