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▲ isaacfrond 2 hours ago

Moreover, it was already known that some NP-complete problems admit sub-exponential algorithms. For example, planar graph 3-colorability can be solved in 2^O(sqrt(n)) time. This is not only sub-exponential, but vastly better than the running time of the new 3-SAT algorithm.

Still, the result is very interesting, since many problems can be solved asymptotically faster once subproblems that can be represented as 3-SAT can be solved faster. For example, we now have now have a deterministic interger factoring algorithm with run time N^o(1), where N is the integer being factored. Heuristic algorithms already achieved this bound, but the new claim is a deterministic worst-case guarantee. The result is a fairly straightforward application of the new 3-SAT solver.

▲tsimionescu 43 minutes ago | parent | next [-]

> For example, we now have now have a deterministic interger factoring algorithm with run time N^o(1), where N is the integer being factored. Heuristic algorithms already achieved this bound, but the new claim is a deterministic worst-case guarantee. The result is a fairly straightforward application of the new 3-SAT solver.

This can't be true unless you're talking about unfathomably large integers, since the new 3SAT algorithm only improves on the 2^n bound for n > 10^100000000. That is, it's not in any way a practical algorithm that will ever be runnable on any possible computer.

▲davidgrenier 2 hours ago | parent | prev [-]

I'm reading O(1.3289^n) for 3-colorability.