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▲ MaulingMonkey a day ago

I prefer:

    const size_t n = 10;
    for (size_t i = n; i --> 0;) {
        std::cout << i << "\n";
    }
▲hedgehog a day ago | parent | next [-]

That's a certain kind of taste... I checked out your home page, game dev, check, and this work of art is worth linking (no irony, I love it):

http://maulingmonkey.com/brainfuck/

▲omoikane a day ago | parent [-]

That looks like the brainfuck mandelbrot set by Erik Bosman, but the example is missing the header line with the credit. The one I saw came from here:

https://github.com/thaliaarchi/bfcorpus/blob/main/ebosman/ma...

Be sure to check out other files in that directory for how the program is assembled.

(Erik Bosman's mandelbrot set is a personal favorite of mine, very useful for benchmarking brainfuck interpreters)

▲ranger_danger a day ago | parent | prev [-]

Cute but wouldn't work with ssize_t :)

VHDL's array/vector syntax actually works a similar way:

-- gives 0, 1, 2, 3:

for i in 0 to 3 loop

-- gives 3, 2, 1, 0:

for i in 3 downto 0 loop

-- Source - https://stackoverflow.com/a/7642026 -- Posted by Kerrek SB -- Retrieved 2026-10-29, License - CC BY-SA 3.0

▲fourthark a day ago | parent [-]

Does work with ssize_t, just not necessary.

▲ranger_danger a day ago | parent [-]

Depends on your definition of "work".

For me it does not work because I'd want to use it with values < 0, but the for loop checks for > 0, so I would have to modify that first.

▲MaulingMonkey a day ago | parent [-]

If you want -3 -2 -1 0 and +3 +2 +1 0 from the same operation, you'll need something more complicated (either some nonsense to give you a signed stride/step value among other things — or perhaps just writing the damn loop twice instead of getting too clever.)

However, if you just want -1 to not iterate down to `std::numeric_limits<ssize_t>::min()` — and then invoke undefined behavior by signed integer underflow if `i` happens to be `ssize_t` instead of `size_t` — I'll note that the `i --> 0` will terminate immediately, unlike `i --` as otherwise seen. (unless you feed it `min()` exactly. Then it'll underflow a signed integer before the comparison, so that's still undefined behavior.)