| ▲ | echoangle 5 hours ago | |
Shouldn’t the expected value of attempting this somehow include the likelihood of the key actually being on the machine? Surely the probability is much higher than 0? I would guess the expected value for actually being the first one is around $300, not 0 | ||
| ▲ | andersonpico 4 hours ago | parent [-] | |
> Surely the probability is much higher than 0 I genuinely have no idea how to even start calculating this probability. How would we do it? Is there reliable data on honeypots? | ||