| ▲ | wk_end 3 hours ago | ||||||||||||||||
Is there an associated machine-checked proof of this? We're in full vibe-code mode at work, so I understand both how powerful frontier models can be and how often they can over-confidently state subtly (or not so subtly) wrong things, even when you're taking great efforts to try to keep that from happening. So without a Lean development or extensive human verification, I guess I'm a little bit skeptical, and even sort of hoping this is wrong - not just because of my not so positive feelings about AI, but by my disposition towards beauty in math. n log n is an awful lot nicer than what we have here. | |||||||||||||||||
| ▲ | bawolff 2 hours ago | parent | next [-] | ||||||||||||||||
Agree 100% on wanting machinr verification of AI generated math. But in regards to beauty, i feel like multiplication already has a lot of non beautiful exponents. Best known matrix multiply is O(n^2.371). For integer factorization, the inverse of this problem, general number field sieve is a crazy subexponential. If factorization is just barely subexponential, is it really that surprising that multiplication is just barely sub n lg n ? | |||||||||||||||||
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| ▲ | reddozen 2 hours ago | parent | prev [-] | ||||||||||||||||
We can just wait for whomever they stole THIS proof from to come forward with threatening emails sent by OpenAI. | |||||||||||||||||