Remix.run Logo
a2ff6eeb0 44 minutes ago

Sure, but I don't know what GCC's behavior is, and I don't vet behavior differences between compiler upgrades. As long as the output works, why does it matter that the black box is deterministic?

rogerrogerr 22 minutes ago | parent [-]

Because _someone_ has vetted the output of GCC. It’s used in flight-critical stuff.

The closest thing we have to vetting LLMs is “whoa look, it escaped this sandbox, that’s prolly not great but it’s so cool!”