> If I do address math on the pointer in order to find a payload, then isn’t the payload tied into exactly one next pointer, and thus exactly one list?

The container_of macro takes the type and member - so for a different member it can subtract a different offset.

Going more basic, you could imagine creating something like:

    struct Node {
        Node* next;
        Node* next_10th;
        Node* next_100th;
    };