| ▲ | cryptonector a day ago | |
If you can do Peano numbers... Guaranteed termination isn't really if you give me enough rope to implement the Ackermann function. | ||
| ▲ | debugnik a day ago | parent [-] | |
Pure Datalog can't express peano up to infinity, its terms can't be functors as in Prolog. At best you could hardcode a successor relation up to a limit. | ||