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| ▲ | 8cvor6j844qw_d6 20 hours ago | parent | next [-] |
| Interesting. I thought 5V is a safe default for USB when in doubt and risk of damage is nil even if it's assumed. |
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| ▲ | seba_dos1 20 hours ago | parent [-] | | Just grab two of these spec-violating chargers and a C-to-C cable. I don't think the right solution to problems coming from spec-violating garbage is producing differently spec-violating garbage. |
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| ▲ | Palomides 21 hours ago | parent | prev | next [-] |
| are there devices that are damaged by 5V? |
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| ▲ | megous 20 hours ago | parent | prev [-] |
| There's nothing dangerous about it. No Type-C receptacle featuring device can assume there will be no Vbus voltage on attachment from the other side, regardless of CC signals. For a simple reason that USB C-A cable assemblies exist and can be plugged to any old charger or port on the A side, which will not wait or negotiate anything. It will just source Vbus 5V right away. |
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| ▲ | crote 20 hours ago | parent [-] | | ... which is exactly why a source with a female USB-C port is not supposed to apply VBUS until it detects a sink. Obvious counterpoint: what's going to happen when two noncompliant "always provide 5V" USB-C wall warts are connected together with a C-C cable? How well does a charger like power being fed into it? | | |
| ▲ | megous 3 hours ago | parent [-] | | Nothing will happen most of the time. Cheapo chargers are usually flyback design which is immune to this. Anyway if you connect anything non-compliant together anything can happen. My point was that always on 5V is no problem for compliant device on the other side. Normal people don't connect two chargers together. :) You can create all kind of fun combos though. Like connecting your PC via USB-A port to a type-c charger, etc. It's all by design safe. USB-A will provide power no matter what, it doesn't matter what CC signals are. |
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