| ▲ | arjvik 2 hours ago | ||||||||||||||||||||||
The way I've learned to read it is
means that `v` is an `int`.
means that `*w` is an `int`, meaning `w` is a pointer to an `int`.
(note that `◌[]` has higher precedence than `*◌`, so this is `*(y[5])`) means that `*y[5]` is an `int`, so `y[5]` is a pointer to an `int`, meaning `y` is an array of `int` pointers.
means that `(*(*kitchensink[5])(int, int))[6]` is an int, so- `*(*kitchensink[5])(int, int)` is an array of `int`. - `(*kitchensink[5])(int, int)` is a pointer to array of `int`. - `kitchensink[5]` is a function pointer to a function that takes `(int, int)` and returns a pointer to an array of `int`. - `kitchensink` is an array of function pointers to functions that take `(int, int)` and return a pointer to an array of `int`. | |||||||||||||||||||||||
| ▲ | kps 2 hours ago | parent [-] | ||||||||||||||||||||||
> int *w; But some misguided style guides demand the misleading `int* w;`, and then act surprised by `int* w, x`; | |||||||||||||||||||||||
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