| ▲ | dmitrygr an hour ago | |||||||||||||||||||||||||||||||
> I assume that a go-around requires less sustained power output than a full climb from takeoff, No. Source 1: PE = mgh Source 2: am pilot | ||||||||||||||||||||||||||||||||
| ▲ | fransje26 4 minutes ago | parent | next [-] | |||||||||||||||||||||||||||||||
So, for a Dash 8-100, at 13,000 kg, disregarding drag, engine efficiency, etc, to take-off and climb to 1000m and accelerate to 150 knots (77 m/s), you will need: - 13000 * 9.81 * 1000 = 127.5 MJ, to reach your altitude - 0.5 * 13000 * (77)^2 = 38.5 MJ, to accelerate to your climbing speed. Total: 127 + 38.5 = 166 MJ, or about 46.11 kWh For a go around, re-accelerating from 1.3 * stall speed (85 knots / 44 m/s) to your climbing speed, and going to your missed approach altitude of 1000 m, you will need: - 13000 * 9.81 * 1000 = 127.5 MJ, to reach your altitude - 0.5 * 13000 * (77^2 - 44^2) = 26 MJ to accelerate back to your climbing speed. Total: 127 + 26 = 153 MJ, or about 42.5 kWh | ||||||||||||||||||||||||||||||||
| ▲ | arijun an hour ago | parent | prev | next [-] | |||||||||||||||||||||||||||||||
You don't do a full climb after a go-around, so the heights are not equal, and the mass is less since you've expended fuel. You also retain some kinetic energy but I assume that is closer to a negligible effect. Also, PE = mgh is probably an not a great formula for energy cost of takeoff/go-around, as there are probably large costs it ignores (gravity loss, less efficient engine use, maybe less efficient turbines?). For your source 2 I have no rebuttal so will have to defer to you, but would ask for an explanation. | ||||||||||||||||||||||||||||||||
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| ▲ | card_zero an hour ago | parent | prev [-] | |||||||||||||||||||||||||||||||
Time to invent regenerative air brakes, like fold-out windmills. | ||||||||||||||||||||||||||||||||
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