| ▲ | dadoum 20 hours ago | |
Good article, but there is one step in the reasoning that rubs me the wrong way: > This equation might seem a little hard to solve, but at this point you might notice something funny: $equation$ > So, if F′(x)log(x)=1,F′(x)log(x)=1, then > Thus, our mystery function F(x)F(x) obeys F′(x)log(x)=1.F′(x)log(x)=1. From here you deduce F′(x)=1/log(x),F′(x)=1/log(x), so by integrating you get But it does not seems that F needs to have that trait, just that 1 works in that instance. It's sufficient but not necessary. How can you tell that it is that simple solution which is the right one? | ||