| ▲ | tasty_freeze an hour ago | |
The article claims: > The Z80 is fully binary compatible with the 8080 instruction set. It wasn't in regards to the flag register. The parity flag behaved differently for some ops. And of course it would be possible to write an 8080 program that used undefined ops that would execute in some random way (often just duplicating an existing instruction) while the Z80 repurposed that opcode for something new. | ||