| ▲ | freehorse an hour ago | |
It is smart, but it is not impossible to crack algorithmically imo. In particular, one can take two consecutive frames and run perturbations moving one frame around (ie shift the indexes) to find where the difference between the two consecutive frames minimises. Then subtract these two (perturbed) frames and ocr it. Works easily if the movement is linear/one-directional. I did this in 20 lines of code (checking only vertical perturbations), and this is what I get with subtracting frame 7 from frame 1: | ||
| ▲ | docheinestages 17 minutes ago | parent | next [-] | |
Do you mind sharing the code? | ||
| ▲ | ctxc 43 minutes ago | parent | prev [-] | |
Nice work! | ||