More like 1 = 0 + 1.

Read about Lisp, the Computational Beauty of Nature, 64k Lisp from https://t3x.org and how all numbers can be composed of counting nested lists all down.

List of a single item:

     (cons '1 nil)

[ 1 | nil ]

List of three items:

    (cons '1 (cons 2 (cons 3 nil)))

    (list '1 '2 '3)

[ 1 | --> [ 2 | -> [ 3 | nil ]

A function is a list, it applies the operation over the rest of the items:

     (plus '1 '2 3') 

Which is like saying:

  (eval '(+ '1 '2 '3))

Eval will just apply the '+' operation to the rest of the list, recursively.

Whis is the the default for every list written in parentheses without the leading ' .

    (+ 1 (+ 2 3))

    (+ '1 '(+ '2 '3)) 

How arithmetic is made from 'nothing':

https://t3x.org/lisp64k/numbers.html

Table of contents:

https://t3x.org/lisp64k/toc.html

Logic, too:

https://t3x.org/lisp64k/logic.html