But compile-time processing is certainly useful in a performance-oriented language.

And not only for performance but also for thread safety (eliminates initialization races, for example, for non-trivial objects).

Rust is just less powerful. For example you cannot design something that comes evwn close to expression templates libraries.

▲ ux266478 15 hours ago | parent | next [-]

> And not only for performance but also for thread safety

This is already built-in to the language as a facet of the affine type system. I'm curious as to how familiar you actually are with Rust?

> Rust is just less powerful.

On the contrary. Zig and C++ have nothing even remotely close to proc macros. And both languages have to defer things like thread safety into haphazard metaprogramming instead of baking them into the language as a basic semantic guarantee. That's not a good thing.

	▲	germandiago 9 hours ago \| parent [-]
		Writing general generic code without repetition for Rust without specialization is ome thing where it fails. It does not have variadics or so powerful compile metaprogramming. It does not come even remotely close. Proc macros is basically plugins. I do not think thos is even part of the "language" as such. It is just plugging new stuff into the compiler.

▲ aw1621107 17 hours ago | parent | prev [-]

> For example you cannot design something that comes evwn close to expression templates libraries.

You keep saying this and it's still wrong. Rust is quite capable of expression templates, as its iterator adapters prove. What it isn't capable of (yet) is specialization, which is an orthogonal feature.

▲ Conscat 16 hours ago | parent | next [-]

Rust cannot take a const function and evaluate that into the argument of a const generic or a proc macro. As far as I can tell, the reasons are deeply fundamental to the architecture of rustc. It's difficult to express HOW FUNDAMENTAL this is to strongly typed zero overhead abstractions, and we see where Rust is lacking here in cases like `Option` and bitset implementations.

	▲	aw1621107 16 hours ago \| parent [-]
		> Rust cannot take a const function and evaluate that into the argument of a const generic Assuming I'm interpreting what you're saying here correctly, this seems wrong? For example, this compiles [0]: `const fn foo(n: usize) -> usize { n + 1 } fn bar<const N: usize>() -> usize { N + 1 } pub fn baz() -> usize { bar::<{foo(0)}>() }` In any case, I'm a little confused how this is relevant to what I said? [0]: https://rust.godbolt.org/z/rrE1Wrx36

▲ menaerus 16 hours ago | parent | prev [-]

> Rust is quite capable of expression templates, as its iterator adapters prove.

AFAIU iterator adapters are not quite what expression templates are because they rely on the compiler optimizations rather than the built-in feature of the language, which enable you to do this without relying on the compiler pipeline.

▲ aw1621107 15 hours ago | parent [-]

I had always thought expression templates at the very least needed the optimizer to inline/flatten the tree of function calls that are built up. For instance, for something like x + y * z I'd expect an expression template type like sum<vector, product<vector, vector>> where sum would effectively have:

    vector l;
    product& r;
    auto operator[](size_t i) {
        return l[i] + r[i];
    }

And then product<vector, vector> would effectively have:

    vector l;
    vector r;
    auto operator[](size_t i) {
        return l[i] * r[i];
    }

That would require the optimizer to inline the latter into the former to end up with a single expression, though. Is there a different way to express this that doesn't rely on the optimizer for inlining?

▲ menaerus 14 hours ago | parent [-]

Expression templates do not rely on optimizer since you're not dealing with the computations directly but rather expressions (nodes) through which you are deferring the computation part until the very last moment (when you have a fully built an expression of expressions, basically almost an AST). This guarantees that you get zero cost when you really need it. What you're describing is something keen of copy elision and function folding though inlining which is pretty much basics in any c++ compiler and happens automatically without special care.

▲ aw1621107 14 hours ago | parent [-]

> since you're not dealing with the computations directly but rather expressions (nodes) through which you are deferring the computation part until the very last moment (when you have a fully built an expression of expressions, basically almost an AST).

Right, I understand that. What is not exactly clear to me is how you get from the tree of deferred expressions to the "flat" optimized expression without involving the optimizer.

Take something like the above example for instance - w = x + y * z for vectors w/x/y/z. How do you get from that to effectively

    for (size_t i = 0; i < w.size(); ++i) {
        w[i] = x[i] + y[i] * z[i];
    }

without involving the optimizer at all?

	▲	menaerus 2 hours ago \| parent [-]
		The example is false because that's not how you would write an expression template for given computation so the question being how is it that the optimizer is not involved is also not quite set in the correct context so I can't give you an answer for that. Of course that the optimizer is generally going to be involved, as it is for all the code and not the expression templates, but expression templates do not require the optimizer in the way you're trying to suggest. Expression templates do not rely on O1, O2 or O3 levels being set - they work the same way in O0 too and that may be the hint you were looking for.