| ▲ | coder68 6 hours ago | |
It does? There is a fast drop followed by a long decay, exponential in fact. The cooling rate is proportional to the temperature difference, so the drop is sharpest at the very beginning when the object is hottest. | ||
| ▲ | amelius 6 hours ago | parent [-] | |
I mean that initial drop doesn't look like it is part of the same exponential decay. | ||