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| ▲ | yorwba an hour ago | parent | next [-] | | For x = -i, square(x) = -1, sqrt(square(x)) = i. Meanwhile, abs(x) = 1. You're right that it simplifies to abs(x) for real x, but that no longer holds for arbitrary complex values. | |
| ▲ | jstanley 3 hours ago | parent | prev [-] | | Right, that's why you need further assumptions on x in order for that simplification to hold. | | |
| ▲ | contubernio 3 hours ago | parent [-] | | It's not a simplification, it's wrong. Sqrt(square(x)) equals abs(x). | | |
| ▲ | MForster 2 hours ago | parent [-] | | It also equals x with appropriate assumptions (x > 0). | | |
| ▲ | notarget137 11 minutes ago | parent | next [-] | | Well, then sin(x) = x if x is infinitely small | |
| ▲ | exe34 43 minutes ago | parent | prev [-] | | so there's an unconditionally correct answer (it's also equal to abs(x) for x>0), and then there is an answer that is only correct for half the domain, which requires an additional assumption. |
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