| ▲ | jph00 2 hours ago | |
> I don’t know how to trust the author if stuff like this is wrong. She's not wrong. A good way to do this calculation is with the log-ratio, a centered measure of proportional difference. It's symmetric, and widely used in economics and statistics for exactly this reason. I.e: ln(1.2/0.81) = ln(1.2)-ln(0.81) ≈ 0.393 That's nearly 40%, as the post says. | ||