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	▲	sebtron 10 hours ago
		This seems to be the best guess so far. But then I am wondering, how is `a () b + c` Parsed then? The precedence of ' is bumped down, but does that mean it has now strictly lower precedence of '+', or the same? In the first case the operation is parsed as `a * (b + c)` In the second case, the "left to right" rule takes over and we get `(a * b) + c` And what happens when there are more than 2 priority groups Taking C has an example, we have that '' has higher precedence than '+' which has higher precedence than '<<' [1]. So `a + b * c << d` Means `(a + (b * c)) << d` Now I could use the "decrease precedence" operator you proposed (possibly proposed by the author?) and write `a + b (*) c << d` Which then bumps down the precedence of '' to... One level lower? Which means the same level of '+', or a level lower, i.e. a new precedence level between '+' and '<<'? Or maybe this operator should end up at the bottom of the precedence rank, i.e. lower than ','? The more I think about this, the less sense it makes... [1] https://en.cppreference.com/w/c/language/operator_precedence...