| ▲ | webignition a day ago | ||||||||||||||||||||||
How many zeros? | |||||||||||||||||||||||
| ▲ | db48x a day ago | parent | next [-] | ||||||||||||||||||||||
Exactly enough to fill out the address, which is always the same length. BTW, IPv4 does basically the same thing. The address 127.1 is equivalent to 127.0.0.1. | |||||||||||||||||||||||
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| ▲ | karlshea a day ago | parent | prev | next [-] | ||||||||||||||||||||||
There are a total of 8 groups of 4 hex digits, so 8 minus however many groups you already have. google.com: 2607:f8b0:4009:819::200e (5 groups) -> 2607:f8b0:4009:0819:0000:0000:0000:200e (3 groups of added zeros) a ULA address: fd2a:1::2 (3 groups) -> fd2a:0001:0000:0000:0000:0000:0000:0002 (5 added) localhost: ::1 -> 0000:0000:0000:0000:0000:0000:0000:0001 | |||||||||||||||||||||||
| ▲ | jstanley a day ago | parent | prev | next [-] | ||||||||||||||||||||||
However many are left. In what circumstances do you care? | |||||||||||||||||||||||
| ▲ | kstrauser a day ago | parent | prev | next [-] | ||||||||||||||||||||||
However many it takes to make the whole A::B number exactly 128 bits long. | |||||||||||||||||||||||
| ▲ | paulddraper a day ago | parent | prev [-] | ||||||||||||||||||||||
“Enough” | |||||||||||||||||||||||