| ▲ | brookst 2 days ago | |||||||||||||||||||||||||||||||
And wouldn’t the solar panels have less cross section than the satellite bodies, so even an apparent collision might just be a very near miss? (Honest question, not rhetorical, could be I’m wrong) | ||||||||||||||||||||||||||||||||
| ▲ | deddy 2 days ago | parent | next [-] | |||||||||||||||||||||||||||||||
This is confusing terminology in the field, but you generally talk about the cross sectional area in the plane of the conjunction (https://www.space-track.org/documents/SFS_Handbook_For_Opera...) to calculate the probability of collision. It’s a conservative definition in the field. It’s generally defined as the hard body radius: take the smallest sphere centered at the center of mass that would entirely enclose the object, then use the maximum cross section of that sphere to define the potential “area” of the colliding object. Maybe put more simply, it’s the worst case area size / orientation you could be looking at. So yes. Solar arrays have a narrow cross section from the side but looking at them head-on (which is the angle used for Pc calculations) they’ll be very large. | ||||||||||||||||||||||||||||||||
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| ▲ | rzimmerman 2 days ago | parent | prev [-] | |||||||||||||||||||||||||||||||
Yeah the solar array on Starlink is held perpendicular to the velocity vector, so the cross section relative to the colliding body will invariably be smaller than the worst case. | ||||||||||||||||||||||||||||||||