Of course, the correct way to use a function pointer is to call it.

▲ nitrix 3 days ago | parent [-]

Yes, the () operator dereference function pointers automatically for you for convenience. There's also the surprise that you can infinitely dereference function pointers as they just yield you more function pointers.

▲ korianders 3 days ago | parent [-]

One baffling thing I see people do with typedefing function pointers is insisting on adding in the pointer part in the typedef which just complicates and hides things.

If you want to typedef a function pointer, make a completely ordinary function declaration, then slap 'typedef' at the beginning, done. This does require you to do "foo_func *f" instead of "foo_func f" when declaring variables, but that is just clearer imo.

    typedef int foo_func(int); // nice

    typedef int (*foo_func)(int); // why?

	▲	cryptonector 3 days ago \| parent [-]
		Why do you need the `*` to be part of every variable/member declaration?