Is your argument that complex powers isn't anything?

xinu2020 an hour ago | parent [-]

Their argument is that ln(z) where z is a complex number is a multi-valued function, so the statement "Explore why i^i is real number" could be misinterpreted as i^i = a single well-defined real value.

	▲	JohnKemeny 12 minutes ago \| parent [-]
		Yes, but it seems strange to claim that i^i isn't anything. That just completely ignores what's interesting, namely that i(π/2 + 2πk) is real for all k ∈ Z.