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| ▲ | CamperBob2 2 days ago | parent [-] | | (Although to be more accurate, it would be what you'd see on an I-V curve tracer if you measured an ideal diode in series with a 1-ohm resistor. The diode by itself would just go vertical at the Y axis, and the ML people would mutter into their beards about exploding gradients.) | | |
| ▲ | hshdhdhehd 2 days ago | parent [-] | | And that diode would be an exploding grenadiant? | | |
| ▲ | CamperBob2 2 days ago | parent [-] | | Yes, because the slope of current versus voltage goes infinite as soon as the voltage goes positive. The math would explode, and so would the diode, given enough current. |
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