▲ | onraglanroad 2 days ago | |||||||
That calculation doesn't make any sense. I mean you both multiply and divide by 10kWh, so those cancel out and you end up with just $ (not "per" anything). What's that supposed to be the price of? I guess if you have 10,000 cycles and one kWh costs $0.014, then that's just the cost of 10,000 kWh. | ||||||||
▲ | torginus 2 days ago | parent [-] | |||||||
I calculated the cost of the pack from the data at $140 for 1kWh. I guess I shouldn't have included the kWh in the divisor but (10000x3.7V2710Ah$0.014) <- total cost of the pack / 10 <- normalize to 1kWh = $140 | ||||||||
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