However C++ offers several overloads where you don't get to provide a drop-in replacement.

Take the short-circuiting boolean operators || and &&. You can overload these in C++ but you shouldn't because the overloaded versions silently lose short-circuiting. Bjarne just didn't have a nice way to write that so, it's not provided.

So while the expression `foo(a) && bar(b)` won't execute function bar [when foo is "falsy"] if these functions just return an ordinary type which doesn't have the overloading, if they do enable overloading both functions are always executed then the results given to the overloading function.

Edited:: Numerous tweaks because apparently I can't boolean today.