▲ | srean a day ago | |
I can't edit my comment anymore so let me elaborate a bit here. What is this sneaky connection between squared Euclidean and Cartesian coordinates that I mentioned ? Why are they such a compatible pair ? The answer is the Pythagorean theorem. The squared Euclidean distances decomposes nicely along orthogonal (perpendicular) directions.
The Cartesian coordinates decomposes a point along orthogonal (perpendicular) axes as well, which we know is special for squared Euclidean distances.The other metrics considered in the blog post decompose as, for lack of a better name, Fermat's last theorem decomposition.
Now if we were to use a coordinate system that decomposes points like that, that would be interesting to explore. I don't know of coordinate systems that do that.This much is true, forget about integral triples (lattice points) for integral n > 2. | ||
▲ | lupire a day ago | parent [-] | |
I don't understand. The Cartesian coordinate system works fine in any norm. See the OP article. |