Remix.run Logo
CamperBob2 5 days ago

Related, but not quite the same thing. Band-limiting is needed to avoid aliasing. The infinite-duration part (or perfect phase continuity at the boundaries, or a window function...) is needed to avoid Gibbs ringing.

An interesting anecdote from Lanczos[1] claims that Michelson (of interferometer fame) observed Gibbs ringing when he tried to reconstruct a square wave on what amounted to a steampunk Fourier analyzer [2]. He reportedly blamed the hardware for lacking the necessary precision.

1: https://math.univ-lyon1.fr/wikis/rouge/lib/exe/fetch.php?med...

2: https://engineerguy.com/fourier/pdfs/albert-michelsons-harmo...

femto 5 days ago | parent [-]

Can we agree that a fun thing about the Fourier Transform is the many different ways such a simple idea (a liner combination of basis functions) can be viewed and the many subtle implications it has?

For example, one viewpoint is that "Gibbs ringing" is always present if the bandwidth is limited, just that in the "non-aliased" case the sampling points have been chosen to coincide with the zero-crossings of the Gibbs ringing.

I find that my brain explodes each time I pick up the Fourier Transform, and it takes a few days of exposure to simultaneously get all the subtle details back into my head.

CamperBob2 5 days ago | parent [-]

For sure. As I understand it, though, the Gibbs phenomenon arises due to the sinc kernel's infinite support (sinc in Fourier domain = rectangular window in time domain, equivalent to no window at all.)

No amount of precision, no number of coefficients, no degree of lowpass filtering can get around the fact that sin(x)/x never decays all the way to zero. So if you don't have an infinitely-long (or seamlessly repeating) input signal, you must apply something besides a rectangular window to it or you will get Gibbs ringing.

There is always more than one way to look at these phenomena, of course. But I don't think the case can be made that bandlimiting has anything to do with Gibbs.