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CamperBob2 6 days ago

No, ECDSA relies on the hardness of the discrete logarithm problem. Nothing to do with factoring, at least not in the classical sense.

On a quantum computer, my understanding is that Shor's algorithm could potentially target both problems, though.

cyberax 6 days ago | parent [-]

Both systems are an example of a hidden Abelian subgroup problem. That is also why Shor's algorithm equally applies to both: https://en.m.wikipedia.org/wiki/Shor%27s_algorithm#Shor's_al...

So a hypothetical classic algorithm that breaks the RSA is also highly likely to break the ECDSA.