▲ | CamperBob2 6 days ago | |
No, ECDSA relies on the hardness of the discrete logarithm problem. Nothing to do with factoring, at least not in the classical sense. On a quantum computer, my understanding is that Shor's algorithm could potentially target both problems, though. | ||
▲ | cyberax 6 days ago | parent [-] | |
Both systems are an example of a hidden Abelian subgroup problem. That is also why Shor's algorithm equally applies to both: https://en.m.wikipedia.org/wiki/Shor%27s_algorithm#Shor's_al... So a hypothetical classic algorithm that breaks the RSA is also highly likely to break the ECDSA. |