▲ | Cthulhu_ 2 days ago | |
Please don't cite ChatGPT as a source or as a caveat, instead show the actual math, which should only be about high school level; kinetic energy formula ½mv² = e, In perfect conditions assuming no loss through drag, you're looking at the kinetic energy formula which is ½mv² = E (in joules). E = 1 kWh = 3,600 kilojoules, velocity v at 10 meters is 14 m/s, so we need to calculate m for v = 14 and E = 3600k, which is just under 36735 kg. "about four of those blocks" is "about" correct. | ||
▲ | michaelgburton 2 days ago | parent [-] | |
Simpler to use the potential energy formula, surely. E = mgh m = E/gh m = 3.6 * 10^6 J / (9.8 m/s^2 * 10m) = 3.6735 * 10^4 kg |