▲ | pklausler 2 days ago | ||||||||||||||||||||||||||||||||||||||||
Division by zero is an error and it should be treated as such. "Infinity" is an error indication from overflow and division by zero, nothing more. | |||||||||||||||||||||||||||||||||||||||||
▲ | sfpotter 2 days ago | parent | next [-] | ||||||||||||||||||||||||||||||||||||||||
This is totally false mathematically. Please look up the extended real number system for an example. Many branches of mathematics affix infinity to some existing number system, extending its operations consistently, and do all kinds of useful things with this setup. Being able to work with infinity in exactly the same way in IEEE754 is crucial for being able to cleanly map algorithms from these domains onto a computer. If dividing by zero were an error in floating point arithmetic, I would be unable to do my job developing numerical methods. | |||||||||||||||||||||||||||||||||||||||||
▲ | ForceBru 2 days ago | parent | prev [-] | ||||||||||||||||||||||||||||||||||||||||
The article's point 3 says that this is a myth. Indeed, the _limit_ of `1/x` as `x` approaches zero from the right is positive infinity. What's more, division by _negative zero_ (which, perhaps surprisingly, is a thing) yields negative infinity, which is also the value of the corresponding limit. If you divide a finite float by infinity, you get zero, because `lim_{x\to\infty} c/x=0`. In many cases you can treat division by zero or infinity as the appropriate limit. | |||||||||||||||||||||||||||||||||||||||||
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