I'm not trying to say anything. I said and meant exactly what I said. No more, no less. Your logic is obviously flawed. There is nothing preventing that optimization in the presence of a forged pointer in bar().

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gpderetta 4 days ago | parent [-]

Either there is no provenance, forging is allowed and the optimization is disallowed; or there is provenance and forging the pointer and attempting to inspect (or modify) the value of *ptr in bar() is UB.

	▲	ncruces 4 days ago \| parent \| next [-]
		You never converted ptr to an integer. If you did, if the pointer escapes, yes, I claim that then the allocation can't be optimized away. Why is that so bad?
	▲	torstenvl 4 days ago \| parent \| prev [-]
		Attempting to inspect or modify the value of *ptr in bar() through a forged pointer was always UB. You are saying absolutely nothing meaningful.