▲ | nullc 2 days ago | |
Tables yuck :P, maybe XOR[0...x] = (x&1^(x&2)>>1)+x*(~x&1) | ||
▲ | bsdz 2 days ago | parent [-] | |
~Is there a simple proof for this type of identity?~ Actually I found something through Gemini based on the table mod 4 idea in previous post. Thanks. |