▲ | dj3l4l 2 days ago | ||||||||||||||||||||||||||||||||||||||||
The Bel is a unitless quantity. Yes, by convention, in certain fields, it applies to the logarithm of the ratio of powers. But in other fields (for example, quantifying a change in the degree of evidence for a hypothesis, as in Bayesian probability theory) it is applied to a ratio of different quantities (in the Bayesian case, a ratio of probabilities). There is no reason why dB can't be used for any unit, and its meaning is incomplete until the denominator of the ratio within the logarithm is known. This is the gripe that is being conveyed in this article. Mathematically, the Bel is unitless. It is only by additional context that one can understand the value of the denominator in the logarithm. | |||||||||||||||||||||||||||||||||||||||||
▲ | kazinator a day ago | parent | next [-] | ||||||||||||||||||||||||||||||||||||||||
Mathematically, the Bel is unitless because it is a function applied to a ratio of measurements. Whatever units those measurements have disappear due to the cancelation. If that measurement is linked to another one in a nonlinear way, that nonlinearity doesn't disappear: the fact that if the unitless fraction in which certain units canceled out is 2, then the corresponding unitless fraction obtained via different units is 4. Just because the units disappeared in a fraction doesn't mean they are not relevant. | |||||||||||||||||||||||||||||||||||||||||
▲ | paipa 2 days ago | parent | prev [-] | ||||||||||||||||||||||||||||||||||||||||
The denominator isn't the issue. The context-dependent base of the logarithm is, which makes 1 Bel = 10x for some things and 1 Bel = 3.16x for others. I've never heard of decibels used in probability theory. Did they adopt it with the same baked-in bastardizations? Please tell me +10dB(stdev) = +10dB(variance) isn't a thing. | |||||||||||||||||||||||||||||||||||||||||
|