▲ | creata 10 hours ago | |
Yeah, I know, I know. But I imagine many people would mentally want to bracket [e for x in xs for y in ys] like [(e for x in xs) for y in ys] and thus conclude that y is the outer loop. | ||
▲ | vram22 an hour ago | parent [-] | |
Yeah, right, mentally want to, jfc, instead of just RTFMing and easily finding out the meaning. Lazy and entitled af. All the rest of us bloody well RTFM. You are special? |