Nice idea, but doesn't this require a linear increase of the length of the partial files and a quadratic size of the original file?

If the length of a file is X, then in the next file you must skip the first X characters and look for a "5" that in average is in the X+128 position. So the average length of the Nth file is 128*N and if you want to reduce C bytes the size of the original file should be ~128C^2/2 (instead of the linear 128*C in the article).

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Dylan16807 7 months ago | parent | next [-]

It does, but that's fine. He only needs to save 150-200 bytes and the file is 3MB. 128*200²/2 is 2.5MB Though I think it would be 256* here? Still, it can be made to work.

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mhandley 7 months ago | parent | prev [-]

Yes, I think it is quadratic. I don't claim it's practical (the original isn't practical either though), but just that the dependency on filenames isn't fundamental.

	▲	gus_massa 7 months ago \| parent [-]
		> I don't claim it's practical Don"t interpret my comment as a complain, I was just triying to understand. This is reposted from time to time, but I don't remember someome proposing this trick before. It's a nice idea.