My quick back of envelope calculations...

Imply that the kinetic energy released upon the impact of such an object, show a group sheltering at the ISS (orbit at an altitude of between 370–460 km (200–250 nmi)) or the Tiangong (orbit between 340 and 450 km (210 and 280 mi) ) would not be likely to survive the impact from ejecta thrown into their orbital altitude...

▲

sebastiennight 8 months ago | parent [-]

OK I'm curious about this bit. How do you deduce the range of height of the ejecta from a calculation of the kinetic energy of the impactor?

▲

belter 8 months ago | parent [-]

You would start with kinetic energy of the impactor using the Kinetic Energy Formula.

https://www.calculatorsoup.com/calculators/physics/kinetic.p...

Let's go with 1.0E+16 Kg for mass and 25000 m/s for impact speed what gives about KE = 3.125E+24 J

Assume 10% of that goes into ejecta.Then use the formula for Velocity from Kinetic Energy.

https://calculator.academy/kinetic-energy-to-velocity-calcul...

What gives about 8000 m/s of initial speed.

Follow that using Maximum Height Formula from kinematics based on a Gravitational acceleration at g: 9.8 m/s²

https://www.omnicalculator.com/physics/maximum-height-projec...

We are looking at eject reaching orbits of 2500 Km to 3000 Km above Earth. Heat and corresponding vaporization effects excluded for simplification purposes.

Now we wait for an event to validate my calculations....

	▲	sebastiennight 7 months ago \| parent [-]
		Taki taki, mi belta kopeng!