| ▲ | enugu 7 days ago | |||||||
One interesting result implies that numbers like 3^(sqrt(3)) will be transcendental (ie no polynomial will evaluate them to 0). https://en.wikipedia.org/wiki/Gelfond%E2%80%93Schneider_theo... | ||||||||
| ▲ | wging 7 days ago | parent | next [-] | |||||||
Small but important correction: no polynomial with integer coefficients (equivalently, rational coefficients). p(x) = (x - 3^(sqrt(3))) is a perfectly fine polynomial with real coefficients. | ||||||||
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| ▲ | immibis 7 days ago | parent | prev [-] | |||||||
No polynomial with rational coefficients. Of course x-y evaluates to 0 when x=y, even if y is a transcendental number. | ||||||||