| ▲ | stavros 6 hours ago | ||||||||||||||||||||||
> It's not UDP socket that gets created here, but Datagram socket A datagram socket is a UDP socket, though. That's what the D stands for. | |||||||||||||||||||||||
| ▲ | jmgao 5 hours ago | parent | next [-] | ||||||||||||||||||||||
Wrong way around: UDP sockets are datagram sockets, there are datagram sockets that are not UDP. | |||||||||||||||||||||||
| ▲ | Quarrel 3 hours ago | parent | prev | next [-] | ||||||||||||||||||||||
To give a more nuanced reply versus the "you're wrong" ones already here, the difference is that UDP adds send and receive ports, enabling most modern users (& uses) of UDP. Hence, it is the "User" datagram protocol. (it also adds a checksum, which used to be more important than it is nowadays, but still well worth it imho.) | |||||||||||||||||||||||
| ▲ | meindnoch an hour ago | parent | prev | next [-] | ||||||||||||||||||||||
Not every cola is Coca-Cola, even though "Cola" stands for cola. | |||||||||||||||||||||||
| ▲ | jdndbdbd 4 hours ago | parent | prev [-] | ||||||||||||||||||||||
No? Why would you think a datagram socket is UDP? | |||||||||||||||||||||||
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