Remix.run Logo
owalt an hour ago

No, it is correct. The integral is with respect to x, and the ordinary/partial derivatives are with respect to t. Written out fully, the derivative computation is

d/dt (x^t - 1)/ln(x) = d/dt [exp(ln(x)t) - 1]/ln(x) = ln(x)exp(ln(x)t)/ln(x) = exp(ln(x)t) = x^t.

Edit: d/dt exp(ln(x)t) = ln(x)exp(ln(x)t) by the chain rule, while d/dt (1/ln(x)) = 0 since the expression is constant with respect to t.

There are convergence considerations that were not discussed in the blog post, but the computations seem to be correct.

impossiblefork an hour ago | parent [-]

Ah, yes. I don't understand how I differentiate with respect to x instead of t, but...