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A triangle whose interior angles sum to zero(johndcook.com)
77 points by tzury 5 hours ago | 33 comments
abhashanand1501 3 hours ago | parent | next [-]

>In spherical geometry, the interior angles of a triangle add up to more than π. And in fact you can determine the area of a spherical triangle by how much the angle sum exceeds π. On a sphere of radius 1, the area equals the triangle excess

To all the flat earthers out there, this property can be used to find out earth is not flat, just by drawing a giant triangle on the surface, without leaving the earth. Historically, to prove the earth is round, people have relied on the sun shining directly overhead on wells in different cities. But this approach proves it without the need to refer the sun.

lwansbrough 11 minutes ago | parent | next [-]

Once you internalize that flat-Earther-ism isn’t about the Earth being flat you realize that rational arguments are pointless.

To expand on that, it’s about community and finding people who share your interests. The movie Behind The Curve explores this idea and it’s quite revealing.

fluoridation 2 hours ago | parent | prev | next [-]

>Historically, to prove the earth is round, people have relied on the sun shining directly overhead on wells in different cities.

That wasn't to prove the Earth is round (and it doesn't prove it). Eratosthenes assumed two things when he performed his experiment: 1) the Earth is round, and 2) the Sun is an infinite distance away. By just this experiment he would have been unable to distinguish between this situation and the Earth being flat while the Sun being only a finite distance overhead (and in fact a fair bit closer than it actually is). Eratosthenes and his contemporaries were already convinced of the roundness of the planet, and he simply wanted to measure it.

>But this approach proves it without the need to refer the sun.

A flat-earther would just tell you that you're not able to maintain a straight path over such long distances without relying on external guides that would definitely put you on curved paths. If the Earth is flat and you stand at 0 N 0 E, how do you move in a straight line East of there? I.e. continuously moving towards the South because the polar coordinates curve towards your left as you progress.

roywiggins an hour ago | parent [-]

>the Earth is flat and you stand at 0 N 0 E, how do you move in a straight line East of there?

This is something that was more or less solved a long time ago with surveying instruments. You don't have to move in a straight line, you build triangles out of sight lines.

fluoridation 28 minutes ago | parent [-]

I can kinda see how that would work, but it presents the challenge that whatever route you plan, it cannot go over water for more than a few kilometers.

roywiggins 9 minutes ago | parent [-]

I don't think it would be that different than the arc measurements that were actually done, you triangulate a bunch of points to work out distances and angle sufficiently precisely:

https://en.wikipedia.org/wiki/Arc_measurement

thaumasiotes 18 minutes ago | parent | prev [-]

> But this approach proves it without the need to refer the sun.

Only if you're happy "proving" your argument to an audience that never had any doubts. You can't use this argument to prove the earth is not flat over the objections of your audience because you can never convincingly show that any given line is straight.

vismit2000 38 minutes ago | parent | prev | next [-]

Girard's Theorem - Spherical Geometry - Deriving The Formula For The Area Of A Spherical Triangle: https://youtu.be/Y8VgvoEx7HY T = r^2 (alpha + beta + gamma - pi)

anigbrowl 2 hours ago | parent | prev | next [-]

Spherical geometers: the trolls of the math world

ethmarks 4 hours ago | parent | prev | next [-]

> Note also that the triangle has infinite perimeter but finite area.

How common is this property in geometry? I know that fractals like the Koch Snowflake also have infinite perimeter over finite area, but I don't know what else does.

IgorPartola 3 hours ago | parent | next [-]

Any function that infinitely slowly converges to a finite number will have this property. Discretely, think of 1/2 + 1/4 + 1/8 and so on. The sequence goes on forever but adds up to 1.

eru 3 hours ago | parent | next [-]

A continuous function with that property is f(x) := 2^-x (when summed over the non-negative part of the x-axis). Another example is g(x) := 1/x^2.

almostgotcaught an hour ago | parent | prev [-]

I have no idea why you think the geometric series has anything to do with this - this is related to continuous but nowhere differentiable functions: https://en.wikipedia.org/wiki/Weierstrass_function

saithound an hour ago | parent [-]

> I have no idea why you think the geometric series has anything to do with this -

IgorPartola is perfectly right to mention geometric series, you can easily use a geometric progression to construct a shape with infinite perimeter and finite area, e.g. by gluing together rectangles with height one and width decreasing in geometric progression. With a bit more thought you can also construct a smooth shape having this property.

almostgotcaught 37 minutes ago | parent [-]

> together rectangles with height one and width decreasing in geometric progression

The geometric series sums to 2 - your glued together rectangles will have perimeter 2*(1+2) and area 2*1.

saithound 10 minutes ago | parent [-]

> your glued together rectangles will have perimeter 2*(1+2)

No. You should think through that perimeter calculation one more time, preferably while drawing a picture.

Here's a hint: the perimeter of a rectangle is no less than its height; you can glue so that the perimeter of each rectangle contributes at least 1 to the perimeter of the union.

nhinck2 4 hours ago | parent | prev [-]

Gabriels Horn for another example.

Doesnt seem that uncommon.

JadeNB 3 hours ago | parent [-]

Gabriel's horn is the same phenomenon one dimension up: finite surface area but infinite volume.

eru 3 hours ago | parent [-]

You mixed it up. The horn has infinite surface area but finite volume.

dkdcio 5 hours ago | parent | prev | next [-]

> infinite perimeter

I don’t follow, how/why?

jerf 5 hours ago | parent | next [-]

The discussion is about triangles in hyperbolic space. In hyperbolic space, if you keep extending a triangle's lines out by moving the intersection farther away, you'll tend toward a triangle with a constant area (pi in the article because the curve was chosen for that, you can have any arbitrary finite value you want by varying the curvature) even though the perimeter keeps going up.

If that sounds like so much technobabble, that's because this article assumed what I think is a very specific level of knowledge about hyperbolic space, as it doesn't explain what it is, yet this is one of the very first things you'll ever learn about it. So it has a rather small target audience of people who know what hyperbolic space is but didn't know that fact about triangles. If you'd like to catch up with what hyperbolic space is, YouTube has a lot of good videos about it: https://www.youtube.com/results?search_query=hyperbolic+spac... And as is often the case with geometry, videos can be a legitimate benefit that is well taken advantage of and not just a "my attention span has been destroyed by TikTok" accomodation.

Including CodeParade's explanations, which are notable in that he made a video game (Hyperbolica) in which you can even walk around in it if you want, with an option for doing it in VR (though that is perhaps the weirdest VR experience I had... I didn't get motion sick per se, but my brain still objected in a very unique manner and I couldn't do it for very long). It's been out and on Steam for a while now, so you can run through the series where he is talking about the game he is in the process of creating at the time and go straight to trying it out, if you want.

gus_massa 5 hours ago | parent | prev | next [-]

Let's go to to the normal infinite plane for a moment.

You can use a map that is inside a circle with r=1. The objects get deformed, but points have a 1 to 1 correspondence. Lines that pass though 0 look straight, but other lines are curved.

Measuring a distance is hard, you have to use some weird rules.

If you draw a segment of length 0.001 segment in the circular map, it has almost the same length in the real infinite map.

If you draw a segment of length 0.001 segment near the border of the circular map, it's a huge thing in the infinite map.

Moreover, a line that pass thorough 0 has apparent length 2 in the map, but represent an infinite length in the plane

Note that the border of the circle is outside the plane.

---

The reverse happen if you have a map of the Earth. You can draw on the map with a pencil a long segment near the pole, but it represents a small curved segment in the Earth.

---

Back to your question ,,,

It's on the hyperbolic plane, not in the usual euclidean plane. So the map is only the top half, and the horizontal line = axis x is outside, it's the border.

Length are weird, and a 0.001 segment draw with a pencil on the map far away from the x axis is small in the actual hyperbolic plane, but a 0.001 segment draw with a pencil on the map near the x axis is very long in the actual hyperbolic plane.

The circles "touch" the x axis. In spite they look short when you draw them with a pencil, they part that is close to the x axis has a huge length in the hyperbolic plane.

kazinator 5 hours ago | parent | prev | next [-]

It must be that the figure with the half circles is just a representation of the hyperbolic space into 2D. Such projections are not faithful; you cannot take measurements in the projection and take them literally.

We can make an analogy to cartography: you can't trust areas and distances on distorted projections like Mercator.

Look, even the angles don't look to be zero in that diagram. We have to imagine that we zoom in on an infinitesimal zone around each corner to see the almost zero angle; i.e. the circle tangent lines actually go almost parallel. So to speak.

Thus the angles are locally correct, since they are measurable on arbitrarily small scales and can easily be imagined to be even when glancing at the entire figure. But distances between the points aren't localizable; they have to follow a measure which somehow correctly spans the abstract hyperbolic space that they represent.

How about this (almost certainly incorrect) imagining: pretend that the real line shown, on which the three points lie, is actually a horizon line, which lies in a vast distance (out at infinity). Just like the horizon when you do drawings with two-point perspective. Imagine the three points are vanishing points on the horizon. Vanishing points are not actually points; they just directions into infinity.

if, in a two-point perspective, you draw a curve whose endpoints are tangent to two vanishing point traces, that curve is infinitely long.

For instance if you draw an intersection between two infinite roads, where the curb has a round corner, you will get some kind of smiley curve joining two vanishing points. That curve is understood to be infinitely long.

dadoum 5 hours ago | parent | prev | next [-]

As far as I understand, the closer the points are to the line, the more distant they get to the rest of the plane. That's why he says that "this is an improper triangle", as the point of intersections of the hyperbolic lines are theoretically at an infinite distance from the "origin", and thus that the lines connecting those points have an infinite length.

roywiggins an hour ago | parent | next [-]

It's a bit analogous to the way train tracks shrink toward the horizon and make an angle with each other where they appear to meet it, even though they don't actually meet in the plane. These hyperbolic lines won't actually ever meet in the hyperbolic plane either but they approach the same point on the horizon.

That edge is basically an artifact of the model, you can equally model the hyperbolic plane space as a disk and then the boundary is a circle, or on an actual hyperboloid in 3D and it extends out forever.

ironSkillet 5 hours ago | parent | prev [-]

The disk model of hyberolic geometry is made to map hyperbolic 2 space (which is infinite in area) into the finite interior of the disk. In order to capture this, the normal euclidean notion of distance is distorted by a function which allows "distances" to go to infinity as a curve approaches the boundary of the disk.

itishappy 5 hours ago | parent | prev [-]

Hyperbolic geometry! Note how lines on the chart don't appear straight. That's because this is just a projection of an infinite hyperbolic space. The rules of this projection move points at infinity to the real line, and straight lines to circles. That means each of the points on the mentioned triangle is infinitely far away in some direction.

ericol 3 hours ago | parent | prev [-]

That's not a fucking triangle.

(It's Friday night people it's a joke and I have no idea what the article is talking about just looked at the picture)

anthonyIPH 3 hours ago | parent | next [-]

I had to reason with my brain before it would accept it as a triangle. It has 3 sides and 3 corners so...

bigstrat2003 3 hours ago | parent [-]

It's one of those things where it's technically correct but the headline is misleading. When you say "a triangle" without any qualification as the headline does, people are going to interpret that as a good old fashioned triangle. Using the term without clarification that you mean spherical geometry is kind of underhanded writing, imo.

cwillu 3 hours ago | parent | next [-]

The title attribute of the article is <title>A hyperbolic triangle with three cusps</title>

eru 3 hours ago | parent | prev [-]

It's a mild form of clickbait.

nurettin 2 hours ago | parent | prev [-]

Sides are half spheres but yeah it is not an euclidean triangle.